Differensiasie: DKP1

$Gebruik space differensiasie space re straight e with ¨ on top ls space en space bepaal space fraction numerator d y over denominator d x end fraction space as space bold italic y bold equals begin bold style left parenthesis 2 minus 5 x right parenthesis end style to the power of bold 2$

Antwoord

$table row cell y equals left parenthesis 2 minus 5 x right parenthesis squared end cell row cell y equals left parenthesis 2 minus 5 x right parenthesis left parenthesis 2 minus 5 x right parenthesis end cell row cell y equals 4 minus 10 x plus 25 x squared end cell row cell fraction numerator d y over denominator d x end fraction equals 0 minus 10 x to the power of 1 minus 1 end exponent plus 25 left parenthesis 2 right parenthesis x to the power of 2 minus 1 end exponent end cell row cell fraction numerator d y over denominator d x end fraction equals negative 10 plus 50 x end cell end table asterisk times minus 10 x to the power of 1 minus 1 end exponent equals negative 10 x to the power of 0 equals negative 10 open parentheses 1 close parentheses equals negative 10$