VRAE oor vraestel 1: eksponente (vergelykings met twee terme)

HI Luca
Baie dankie vir jou som! Dis 'n goeie een!

Ek neem aan jy het gesien dat jy jou breuk weggegooi het, terwyl hy eintlik nog daar was. Ek gaan vir jou twee maniere wys hoe ek die som sou doen - ek verkies die eerste een. (",)

Opsie#1

table row cell 2 over 3 to the power of x minus 5 end exponent equals 162 end cell blank blank blank row cell 2 equals 162.3 to the power of x minus 5 end exponent end cell blank blank cell Maal space met space die space KGV end cell row cell 2 over 162 equals 3 to the power of x minus 5 end exponent end cell blank blank cell Deel space die space konstante space weg end cell row cell 1 over 81 equals 3 to the power of x minus 5 end exponent end cell blank blank Vereenvoudig row cell 1 over 3 to the power of 4 equals 3 to the power of x minus 5 end exponent end cell blank blank cell Skryf space grondgetalle space straight a space spriemfaktore end cell row cell 3 to the power of negative 4 end exponent equals 3 to the power of x minus 5 end exponent end cell blank blank cell Raak space van space breuk space ontslae end cell row cell negative 4 equals x minus 5 end cell blank blank cell Gooi space grondgetalle space weg end cell row cell negative 1 equals x end cell blank blank blank row cell x equals negative 1 end cell blank blank blank end table

Ek hou die meeste van die oplossing hierbo, want jy raak dadelik van die funny breuk ontslae en dan lyk die som soos enige maklike een.

Opsie#2

table row cell 2 over 3 to the power of x minus 5 end exponent equals 162 end cell blank blank blank row cell 2 over 3 to the power of x minus 5 end exponent equals 2.3 to the power of 4 end cell blank blank cell Skryf space konstantes space as space priemfaktore end cell row cell fraction numerator 2 over denominator 3 to the power of x 3 to the power of negative 5 end exponent end fraction equals 2.3 to the power of 4 end cell blank blank cell Split space die space eksponente end cell row cell 2.3 to the power of negative x end exponent.3 to the power of plus 5 end exponent equals 2.3 to the power of 4 end cell blank blank cell Skuif space noemers space boontoe space en space verander space hulle space tekens end cell row cell 3 to the power of negative x end exponent equals fraction numerator 2.3 to the power of 4 over denominator 2.3 to the power of 5 end fraction end cell blank blank cell Deel space konstantes space weg end cell row cell 3 to the power of negative x end exponent equals 3 to the power of negative 1 end exponent end cell blank blank Vereenvoudig row cell negative x equals negative 1 end cell blank blank cell Gooi space grondgetalle space weg end cell row cell x equals 1 end cell blank blank blank end table

Ek hou persoonlik nie baie van hierdie manier nie, dit voel vir my lomp en lank, but that's just me (",)

Hoop dit help?