VM#2

VM#2

by Marna Zuhlsdorff -
Number of replies: 0

Herskryf die volgende vergelyking in terme van b: fraction numerator bold a bold x over denominator bold b end fraction bold minus fraction numerator bold b bold x over denominator bold a end fraction bold equals bold a over bold b bold plus bold 1

table row cell fraction numerator a x over denominator b end fraction minus fraction numerator b x over denominator a end fraction equals a over b plus 1 end cell row cell K G V equals a b end cell row cell a open parentheses a x close parentheses minus b open parentheses b x close parentheses equals a open parentheses a close parentheses plus 1 open parentheses a b close parentheses end cell row cell a squared x minus b squared x equals a squared plus a b end cell row cell x open parentheses a minus b close parentheses open parentheses a plus b close parentheses equals a open parentheses a plus b close parentheses end cell row cell x a minus x b equals a end cell row cell negative x b equals a minus x a end cell row cell negative x b equals a open parentheses 1 minus x close parentheses end cell row cell b equals fraction numerator a open parentheses 1 minus x close parentheses over denominator negative x end fraction end cell end table