VBT#1

VBT#1

by Marna Zuhlsdorff -
Number of replies: 0

Bepaal die waarde van y: \( \frac{3}{{y - 1}} + \frac{2}{{1 - y}} = 1 \)

\( \begin{align} \frac{3}{{y - 1}} + \frac{2}{{1 - y}} &= 1\\ \frac{3}{{\left( {y - 1} \right)}} - \frac{2}{{\left( {y - 1} \right)}} &= 1\\ KGV &= \left( {y - 1} \right) \\ 3 - 2 &= 1\left( {y - 1} \right)\\ 1 &= y - 1\\ y &= 2 \end{align} \)

Beperking

\( \begin{align} y - 1 &\ne 0\\ y &\ne 1 \end{align} \)