Bepaal die waarde(s) van x en kies die regte antwoord:
\( \frac{{3 - x}}{{\left( {x + 3} \right)\left( {x + 1} \right)}} = \frac{2}{{x + 1}} \)
\( \begin{align} \frac{{3 - x}}{{\left( {x + 3} \right)\left( {x + 1} \right)}} &= \frac{2}{{x + 1}}\\ \frac{{ - \left( {x - 3} \right)}}{{\left( {x + 3} \right)\left( {x + 1} \right)}} &= \frac{2}{{x + 1}}\\ KGV &= \left( {x +
3} \right)\left( {x + 1} \right) & \\ - \left( {x - 3} \right) &= 2\left( {x + 3} \right)\\ - x + 3 &= 2x + 6\\ 3 - 6 &= 2x + x\\ - 3 &= 3x\\ x &= - 1\\ maar\,\,x &\ne - 1\,\,\left( {{\rm{beperking}}} \right)\\
& \therefore {\rm{geen\,\,oplossing}} \end{align} \)
Beperkings:
\( \begin{align} x + 3 &\ne 0\\ x &\ne - 3 \end{align} \)
\( \begin{align} x + 1 &\ne 0\\ x &\ne - 1 \end{align} \)