OPSIE 1

\( \( \begin{align} \left( {x + 3} \right)\left( {x - 1} \right) &= - x + 1\\ {x^2} + 2x - 3 &= - x + 1\\ {x^2} + 3x - 4 &= 0\\ {x^2} + 3x + {\left( {\frac{3}{2}} \right)^2} - {\left( {\frac{3}{2}} \right)^2} - 4 &= 0\\ {\left( {x + \frac{3}{2}} \right)^2} - \frac{{25}}{4} &= 0\\ {\left( {x + \frac{3}{2}} \right)^2} &= \frac{{25}}{4}\\ x + \frac{3}{2} &= \pm \sqrt {\frac{{25}}{4}} \\ x + \frac{3}{2} &= \pm \frac{5}{4}\\ x + \frac{3}{2} &= + \frac{5}{4} &of& &x + \frac{3}{2} &= - \frac{5}{4}\\ x &= - \frac{1}{4}&& &x &= - \frac{{11}}{4} \end{align} \) \)

OPSIE 2

\( \begin{align} \left( {x + 3} \right)\left( {x - 1} \right) &= - x + 1\\ {x^2} + 2x - 3 &= - x + 1\\ \left( {x + 3} \right)\left( {x - 1} \right) &= - x + 1\\ {x^2} + 2x - 3 &= - x + 1\\ {x^2} + 3x &= 4\\ {x^2} + 3x + {\left( {\frac{3}{2}} \right)^2} &= 4 + {\left( {\frac{3}{2}} \right)^2}\\ {\left( {x + \frac{3}{2}} \right)^2} &= \frac{{25}}{4}\\ x + \frac{3}{2} &= \pm \sqrt {\frac{{25}}{4}} \\ x + \frac{3}{2} &= \pm \frac{5}{4}\\ x + \frac{3}{2} &= + \frac{5}{4} &of& &x + \frac{3}{2} &= - \frac{5}{4}\\ x &= - \frac{1}{4} && &x &= - \frac{{11}}{4} \end{align} \)