Los op vir x en kies die regte antwoord as \( {\left( {2x - 3} \right)^2} = 1 \)

\( \begin{align} {\left( {2x - 3} \right)^2} &= 1\\ \sqrt {{{\left( {2x - 3} \right)}^2}} &= \pm \sqrt 1 \\ 2x - 3 &= \pm 1\\ x &= \frac{{3 \pm 1}}{2}\\ x &= \frac{{3 - 1}}{2}\,\,\,\,of\,\,\,\,&&x= \frac{{3 + 1}}{2}\\ x &= 1&&x = 2 \end{align} \)