AN meetkunde - sirkel vergelyking

AN meetkunde - sirkel vergelyking

by Jolinda de Kock -
Number of replies: 1



(Edited by Marna Zuhlsdorff - original submission Tuesday, 25 February 2020, 3:56 PM)

In reply to Jolinda de Kock

Re: AN meetkunde - sirkel vergelyking

by Marna Zuhlsdorff -

Hi Jolinda

Baie dankie vir jou vraag en bewerking - jy is 'n derde pad daar met jou antwoord (",)

Onthou, wanneer ons die vergelyking van 'n sirkel wil uitwerk en ons twee goed nodig: die middelpunt en die radius. Hierdie twee waardes vervang ons dan in die algemene vergelyking in om die spesifieke vergelyking van ons spesifieke sirkel te kry.

Jy kan hier click as jy weer die video wil kyk.

Eers werk ons die middelpunt en die radius uit:

m i d d e l p u n t colon table row cell M subscript M equals open parentheses fraction numerator x subscript D plus x subscript O over denominator 2 end fraction semicolon fraction numerator y subscript D plus y subscript O over denominator 2 end fraction close parentheses end cell row cell open parentheses a semicolon b close parentheses equals open parentheses fraction numerator negative 2 plus 0 over denominator 2 end fraction semicolon fraction numerator negative 2 plus 0 over denominator 2 end fraction close parentheses end cell row cell open parentheses a semicolon b close parentheses equals open parentheses negative 1 semicolon minus 1 close parentheses end cell end table

e e r s space d i e space d e u r s n e e table row cell O D equals square root of open parentheses y subscript D minus y subscript O close parentheses squared plus open parentheses x subscript D minus x subscript O close parentheses squared end root end cell row cell equals square root of open parentheses negative 2 minus 0 close parentheses squared plus open parentheses negative 2 minus 0 close parentheses squared end root end cell row cell equals 2 square root of 2 end cell end table n o u space d i e space r a d i u s table row cell r equals fraction numerator O D over denominator 2 end fraction end cell row cell equals fraction numerator 2 square root of 2 over denominator 2 end fraction end cell row cell equals square root of 2 end cell end table

Ek verkies om nie die middelpunt in my bewerking te gebruik nie - vir ingeval ek dalk 'n fout gemaak het, daarom werk ek eers die deursnee uit en deel dit dan met 2 om die radius te kry.

Nou vervang ons als in die algemene vergelyking in:
table row cell open parentheses x minus a close parentheses squared plus open parentheses y minus b close parentheses squared equals r squared end cell row cell open parentheses x minus open parentheses negative 1 close parentheses close parentheses squared plus open parentheses y minus open parentheses negative 1 close parentheses close parentheses squared equals open parentheses square root of 2 close parentheses squared end cell row cell open parentheses x plus 1 close parentheses squared plus open parentheses y plus 1 close parentheses squared equals 2 end cell end table

En daar is ons klaar! (",)
Is alles duidelik genoeg vir jou?
Laat my weet.

Marna