VRAE oor vraestel 1: Algebraiese breuke - vereenvoudiging met trick

Hi Charles
Dankie vir jou vraag! Hier moet jy die *trick* gebruik om die onderste hakie dieselfde as die boonste een te maak, want

open parentheses 4 minus 5 x close parentheses not equal to open parentheses 5 x minus 4 close parentheses

table row cell space space space space fraction numerator 25 x squared minus 16 over denominator 4 minus 5 x end fraction end cell blank blank blank row cell equals fraction numerator open parentheses 5 x minus 4 close parentheses open parentheses 5 x plus 4 close parentheses over denominator 4 minus 5 x end fraction end cell blank blank cell Verskil space in space vierkante space bo end cell row cell equals fraction numerator open parentheses 5 x minus 4 close parentheses open parentheses 5 x plus 4 close parentheses over denominator negative open parentheses 5 x minus 4 close parentheses end fraction end cell blank blank cell trick space onder end cell row cell equals fraction numerator up diagonal strike open parentheses 5 x minus 4 close parentheses end strike open parentheses 5 x plus 4 close parentheses over denominator negative up diagonal strike open parentheses 5 x minus 4 close parentheses end strike end fraction end cell blank blank cell Kanselleer space uit end cell row cell equals fraction numerator open parentheses 5 x plus 4 close parentheses over denominator negative 1 end fraction end cell blank blank blank row cell equals negative open parentheses 5 x plus 4 close parentheses end cell blank blank blank end table