VKE#4

VKE#4

by Marna Zuhlsdorff -
Number of replies: 0

Los op vir x as \( x\left( {{x^2} - 5} \right)\left( {x + 7} \right)\left( {2x - 1} \right) = 0 \)

\( x\left( {{x^2} - 5} \right)\left( {x + 7} \right)\left( {2x - 1} \right) = 0\\ \)

\( {x = 0} \)

\( \begin{align} {x^2}- 5&=0 \\ x&=\pm \sqrt 5 \end{align} \)

\( \begin{align} x+7&=0 \\ x&=-7 \end{align} \)

\( \begin{align} 2x-1&=0 \\ x&=\frac{1}{2} \end{align} \)

\( \therefore x = \left\{ { - 7; - \sqrt 5 ;0;\frac{1}{2};\sqrt 5 } \right\} \)