Getallestelsels: RGE#1

Gebruik die volgende groep breuke $open curly brackets negative 15 over 20 semicolon 25 over 30 semicolon 30 over 60 semicolon fraction numerator negative 48 over denominator 18 end fraction close curly brackets$ en vind ‘n ekwivalente breuk vir elk van die volgende:

a) $1 half$

negative 2 2 over 3

c) $5 over 6$

d) $negative 75 over 100$

a)
$table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 1 cross times 15 over denominator 2 cross times 15 end fraction end cell equals cell 30 over 60 end cell row blank blank cell o f end cell row cell fraction numerator 30 divided by 15 over denominator 60 divided by 15 end fraction end cell equals cell 1 half end cell row cell therefore 1 half end cell equals cell 30 over 60 end cell end table$

b)
$negative 2 space 2 over 3 equals negative fraction numerator 8 cross times 6 over denominator 3 cross times 6 end fraction space equals negative 48 over 18 o f table attributes columnalign right center left columnspacing 0px end attributes row cell negative fraction numerator 48 divided by 6 over denominator 18 divided by 6 end fraction end cell cell equals negative end cell cell 8 over 3 equals negative 2 space 2 over 3 end cell end table therefore minus 2 space 2 over 3 equals negative 48 over 18$

c)
$table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 5 cross times 5 over denominator 6 cross times 5 end fraction end cell equals cell 25 over 30 end cell row blank blank cell o f end cell row cell fraction numerator 25 divided by 5 over denominator 30 divided by 5 end fraction end cell equals cell 5 over 6 end cell row cell therefore 5 over 6 end cell equals cell 25 over 30 end cell end table$

d)
$table attributes columnalign right center left columnspacing 0px end attributes row cell negative fraction numerator 75 divided by 5 over denominator 100 divided by 5 end fraction end cell cell equals negative end cell cell 15 over 20 end cell end table o f minus fraction numerator 15 cross times 5 over denominator 20 cross times 5 end fraction space equals negative 75 over 100 therefore minus 75 over 100 equals negative 15 over 20$